与早期版本的潜在不兼容性

PyQt4 v4.11

Python 槽的执行

Until the release of PyQt4 v4.9.4, when a signal was emitted to a Python slot that was not decorated with pyqtSlot() , it would first check that the underlying C++ receiver instance still existed. If it didn't then the slot was ignored thereby reflecting the standard C++ behaviour.

In v4.9.4 (strictly speaking it was the release of SIP at the time) the check was removed. It was done so that an object could connect its destroyed() signal to itself so that it could monitor when its underlying C++ instance was destroyed. Unfortunately this turned out to be an undocumented and incompatible change and a potential source of obscure bugs for more common code.

In v4.11 the check was reintroduced - hence creating an incompatibility for any code that relies on the v4.9.4 behaviour. As a workaround for this the no_receiver_check argument has been added to connect() which allows the check to be suppressed on a per connection basis.

PyQt4 v4.9.2

QPyNullVariant

In previous versions a QPyNullVariant would always evaluate to True when converted to a bool.

在此版本 QPyNullVariant will always evaluate to False when converted to a bool. This makes it behave like None in these circumstances.

PyQt4 v4.8.3

SQL 模型

In previous versions, when using v2 of the QVariant API (the default for Python v3), there was no way to represent a null QVariant . Therefore when reading values of certain types from an SQL model it was impossible to distinguish between, for example, a null integer and an integer with the value zero.

In this version the QPyNullVariant class is used to represent a null QVariant. Therefore the object read from an SQL model may now be a QPyNullVariant 实例。

A null QVariant is only converted to a QPyNullVariant if the underlying C++ type of the QVariant cannot be tested for null, i.e. it does not implement an isNull() method. This ensures that existing code that uses non-SQL models will continue to work unchanged.

PyQt4 v4.8

QVariantList

In previous versions PyQt4 would always try and convert a Python list to a QVariantList . In this version PyQt4 will first try to convert it to a QVariant 包含 QList<QObject *> , but only if QList<QObject *> has been registered with Qt as a meta-type.

Normally it is only the QtDeclarative module that registers this meta-type and so the behaviour of existing applications should be unchanged. It is possible however that you might observe different conversion behaviour after importing the QtDeclarative 模块。

PyQt4 v4.7.4

pyqtSignal() with dict and list

In previous versions a Qt signal defined using pyqtSignal() that had an argument specified as a dict then, when emitting a value, PyQt4 would try and convert the value to a QVariantMap if possible. If it wasn't possible, normally because the dict had non-string keys, then the value would be left as a dict object.

In this version PyQt4 will not attempt to convert the value to a QVariantMap and will always leave it as a dict object. If you want the value to be converted to a QVariantMap then define the signal argument as 'QVariantMap' .

The same applies to conversions between lists and QVariantList .

PyQt4 v4.7.1

QVariant

This version introduces a slight incompatibility in the conversion between sub-classes of standard Python types and QVariant .

Take, for example, the following code:

from PyQt4.QtCore import QVariant
class MyFloat(float):
    pass
myfloat = MyFloat(5.0)
variant = QVariant(myfloat)
									

With this version of PyQt4 myfloat will be converted in such a way as to preserve any additional attributes (including methods) and will not be converted to a C++ double . In other words, the following assertions are true:

assert(variant.type() != QVariant.Double)
assert(variant.toPyObject() is myfloat)
									

Prior to this version myfloat would be converted to a C++ double . In other words, the following assertions would be true:

assert(variant.type() == QVariant.Double)
assert(variant.toPyObject() == myfloat)
assert(type(variant.toPyObject()) is float)
									

The same change also affects objects that implement the sequence protocol. Prior to this version such an object would be converted to a QVariantList which would mean that it was converted back to a Python list rather than to the original type.

PyQt4 v4.5

QVariant

This version introduces a slight incompatibility in the conversion between Python sub-classes of certain Qt classes and QVariant . The Qt classes affected are those that QVariant has explicit support for, e.g. QSize , QBitmap .

Take, for example, the following code:

from PyQt4.QtCore import QSize, QVariant
class MySize(QSize):
    pass
mysize = MySize(5, 5)
variant = QVariant(mysize)
									

With this version of PyQt4 mysize will be converted in such a way as to preserve any additional attributes (including methods) and will not be converted to a C++ QSize instance. In other words, the following assertions are true:

assert(variant.type() != QVariant.Size)
assert(variant.toPyObject() is mysize)
									

Prior to this version mysize would be converted to a C++ QSize instance. In other words, the following assertions would be true:

assert(variant.type() == QVariant.Size)
assert(variant.toPyObject() == mysize)
assert(type(variant.toPyObject()) is QSize)
									

It is hoped that this change of behaviour will not have a significant impact. However if you need the old behaviour then simply create a copy of your sub-class instance using the base class constructor as shown below:

variant = QVariant(QSize(mysize))
									

A similar issue also affects the conversion of the Python datetime , date and time types to QVariant . These are no longer converted to the corresponding QDateTime , QDate and QTime classes. The values can be retrieved using QVariant.toPyObject() . Again, the old behaviour can be achieved using an explicit conversion to the Qt class before converting to QVariant .

A further incompatible change is the handling of Python sub-classes of QObject . In previous versions QVariant.userType() would return an internal type and an extra reference would be kept to the Python object. In the current version QVariant.userType() will correctly return QMetaType.QObjectStar (或 QMetaType.QWidgetStar ) but an extra reference to the Python object is not kept. To avoid a potential crash you should ensure that you keep a separate reference to the Python object, either explicitly or implicitly by giving it a parent.

pyrcc4 支持 Python v3

pyrcc4 will now generate code for Python v3 when the new -py3 command line option is used. The generated code will also work with Python v2.6 and later.

默认情况下 pyrcc4 will generate code for all Python v2 versions but you should use the new -py2 command line option to enforce this in case the default is changed in the future.